3.33x+2x^2-1=0

Solution for 3.33x+2x^2-1=0 equation:

3.33x+2x^2-1=0

a = 2; b = 3.33; c = -1;
Δ = b2-4ac
Δ = 3.332-4·2·(-1)
Δ = 19.0889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.33)-\sqrt{19.0889}}{2*2}=\frac{-3.33-\sqrt{19.0889}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.33)+\sqrt{19.0889}}{2*2}=\frac{-3.33+\sqrt{19.0889}}{4}
$